Sigting in from an elevated position

S

shredder4286

New member
Our backyard rifle range is 100 yds, but the bench is about 10' higher than the target.

What I'm wondering is- how much different will my p.o.i be if I were to take a shot at 100 yds without being elevated after being sighted in from the elevated bench? (I.e. hunting)

I'm assuming it would make some difference, just not sure how much.
 
Cosine angle times range equals true horizontal distance for drop.

By my math that is a 1.9 degree slope.

Cosine 1.9 x 300(feet) = 299.8 feet.

Jimro
 
Cosine angle times range equals true horizontal distance for drop.

By my math that is a 1.9 degree slope.

Cosine 1.9 x 300(feet) = 299.8 feet.

Jimro
Click to expand...

So, by math, the difference would be .2 feet of difference in drop. That's what I needed to know- thanks folks!!:D
 
No; JIMRO's math is saying that your effective range is 299 ft vs. 300 on level ground. Your difference in drop is going to be immeasurable... just in case his answer was misconstrued.
 
So, by math, the difference would be .2 feet of difference in drop. That's what I needed to know- thanks folks!!
Click to expand...

It means that the angular correction is only .2 feet. The difference in bullet drop over .2 feet is smaller than I care to calculate, but I'm sure it is less than even the adjustments of the finest 1/8 MOA scope.

Just zero as normal.

For what it is worth, whenever you shoot uphill or downhill, you don't get into "interesting" differences in bullet impact until you are more than 25 degrees of slope, which gives you a 10% reduction in range to correct for. Which means at 1000 yards, with a 25 degree slope, you would use your 900 yard zero.

At short ranges and small angles, it really doesn't matter. In fact, anything inside your point blank range is "point and pull" no matter the angle, if you use a +/- 2" pbr zero.

Jimro
 
It means that the angular correction is only .2 feet. The difference in bullet drop over .2 feet is smaller than I care to calculate, but I'm sure it is less than even the adjustments of the finest 1/8 MOA scope.

Just zero as normal.

For what it is worth, whenever you shoot uphill or downhill, you don't get into "interesting" differences in bullet impact until you are more than 25 degrees of slope, which gives you a 10% reduction in range to correct for. Which means at 1000 yards, with a 25 degree slope, you would use your 900 yard zero.

At short ranges and small angles, it really doesn't matter. In fact, anything inside your point blank range is "point and pull" no matter the angle, if you use a +/- 2" pbr zero.

Jimro
Click to expand...

Ok. 10% reduction in range for 25 deg slope. Putting that one in the "gun notes" file. Thanks for the info. Got more than I expected out of this one. :cool:
 
Just remember that in the common hunting distances, even ten percent doesn't have much effect on trajectory.

If you're sighted in for 200 yards, the usual drop for most deer cartridges at 300 yards is about six inches.

The drop at 270 yards would be around five inches. The one-inch difference is hardly worth worrying about.
 
Just remember that in the common hunting distances, even ten percent doesn't have much effect on trajectory.

If you're sighted in for 200 yards, the usual drop for most deer cartridges at 300 yards is about six inches.

The drop at 270 yards would be around five inches. The one-inch difference is hardly worth worrying about.
Click to expand...

Hey, absolutely, Art. That being said- my rifle isn't even being sighted in at a 25 degree slope, so it's even less than a 10% decrease. I just thought it was interesting to know the actual mathematic equation to figure out what I needed to know.
 
You must log in or register to reply here.
Back
Top