All that math goes out the window when we consider a target as complex as the human body. Just some of the other factors to consider would be shot placement, clothing, angle, trajectory, bullet composition, and bullet size. Then work out the equation while Torgo's running at me with a gram of cocaine in his system, a piece of rebar in his hand, and murder in his eyes. Yeah.The area of a hole from .452 inch bullet would be pi*.226^2= .16037864 square inches
The area of a hole from two .356 inch bullets would be 2*(pi*.178^2)= .19897552 square inches
So, unless someone has something novel to contribute, this is yet another "9mm vs. .45" thread.