I don't mean to sound preachy but you guys are way off about semiautos and pressure. Unless you have a very rare "gas operated" semiauto pistol, there is no pressure loss because of the slide movement. All the pressure of the cartridge pushes the bullet out the barrel. Recoil is what drives the slide to the rear. That pesky guy Newton had it figured out in his second law (I think). For every action there is an equal and opposite reaction.
Second, someone above was correct in that most semiauto barrels include the chamber while revolver barrels do not include the cylinder (chambers). Thus, a 5" pistol barrel is not the same in terms of performance as a 5" revolver barrel. It would seem, from the above that revolvers would have an edge but they loose that edge because of the barrel/cylinder gap, which does loose pressure. You can't say as a matter of fact that all revolvers will have less performance (velocity) than auto pistols because the cartridge, the powder, and several other variables come into play.
Preception is often that revolvers have more power but this is more often than not a case of "felt recoil" being greater. I had a 5" M25 S&W that I used to let people shoot along side my 5" Government model. Every single person who tried the two insisted that the ammumition in the revolver was hotter than the ammo in the pistol. This was after I loaded both out of the same box of 45 ACPs.
The axis of the bore for the revolve rides higher, thus the recoil force is generated higher above the wrist, making it feel like it kicks harder. The axis of the bore for the auto pistol generally rides lower, and the recoil impulse is partially absorbed in pushing the slide to the rear. Thus, the auto feels like it kicks less.
To the new shooter all the above could well make you believe "revolvers hit harder than autos".
Dave T
PCSD Ret.