Point of impact

T

taco

New member
Can anybody here tell me where the bullet will hit if I sight-in the iron sight on my AR-15 shorty using 55gr ball ammo at 100 yards at various distance? Velocity is 2,850 fps from my AR.

I'm interest in point of impact vs. point of aim at:

10 yards
25 yards
50 yards
75 yards
100 yards (this should be +/-0)
150 yards
200 yards
250 yards
300 yards
400 yards
500 yards

Any place on the web where I can find this information?

Thanks for any help.
 
Possible plagerize

from Sierra's Rifle Reloading manual, 4th Ed., the bullet path height can be calculated with

yb(R)+[y(R)-hs]+(R/Rz)(hs-yz)

where
yb(R)=bullet path ht in inches at range R
positive values = above sight line
R = the range from the muzzle at which yb is to be calc.
y(R)=is bullet drop (neg) at range R
inches, from drop tables
hs= height of sights above bore centerline (pos)
Rz= zero range in yds
yz=drop in inches at zero range

It's probably a good idea to obtain a reloading manual.
Since your muzzle v is between 2800 and 2900, the tables in the back of a manual won't give you exactly what you're looking for, but it will be a good start. They also don't have all the distances. They usually have all the basics, (50, 100, 200, 500, 600...), but you can probably extrapolated these with a little neurotransmitter grease.

There are some good computer ballistics programs out, (Sierra's being one of them). There are also some on the Internet. A search on "Ballistics" might help.

Hope this helped.
 
Do you need specifics or do you want something that you can remember?
Zero you iron sights at 25 Yards and your also zeroed at 250. At mid flight between the two points you are about 3 inchs high. At 300 your about 3 inches low.
So you zero at 25 at aim for center mass and you have a good fighting zero.
 
echo3mike,

That's a little too confusing for an old grunt. I'll stick with the 25 yard zero that George mentioned.

Turk
 
funny....

I'm a middle aged (OMG) fmr. grunt / groundpounder and I remember it just fine. Of course, it's programmed into a scientific calculator, so there's memory involved somewhere.

Just not mine!

George's idea is alot easier to remember.
 
I might be a little off... but thats the ballpark...
A heavier bullet might have a bigger arch - but that would push you to 4 high and 6 low... Still a pretty flat trajectory that will let you still hit your target if you aim center of mass. I've used that zero since my first ARM course at FT. Benning in 1987
 
You must log in or register to reply here.
Back
Top