RougeLeader
Inactive
Hello everyone! I've been working up a 38 Special load based on my 44th edition Lyman manual (10.7gn 2400 topped by a 158 LSWC) and have been warned multiple times to be careful.
In doing my research ahead of time, I found many warnings of firearm failures, or Kabooms, but I didn't find many details of how exactly they would fail. I also found warnings that the old stout loads and 38/44 loads were designed for N Frames and other revolvers of similar cylinder size.
My question is how exactly revolvers fail when you push things too far with powder. I understand a double charge can certainly burst the case and the cylinder, but even a 357 load doesn't really seem to deform the case itself to any significant degree, much less stress the cylinder around the case. Is it the freebore portion of the the cylinder directly after the case mouth that fails? Is it the frame itself that fails under the force of the cartridge being fired?
Before anyone gets concerned, I'm not intending to blow anything up. I'm a grad student in a combustion engineering lab at the University of Connecticut (yes I know, please be kind) and am well aware of the dangers of explosives of any kind. The load I'm working with is safe, and I already have ~500 fired out of a K Frame. I'm merely curious from a theoretical standpoint.
In doing my research ahead of time, I found many warnings of firearm failures, or Kabooms, but I didn't find many details of how exactly they would fail. I also found warnings that the old stout loads and 38/44 loads were designed for N Frames and other revolvers of similar cylinder size.
My question is how exactly revolvers fail when you push things too far with powder. I understand a double charge can certainly burst the case and the cylinder, but even a 357 load doesn't really seem to deform the case itself to any significant degree, much less stress the cylinder around the case. Is it the freebore portion of the the cylinder directly after the case mouth that fails? Is it the frame itself that fails under the force of the cartridge being fired?
Before anyone gets concerned, I'm not intending to blow anything up. I'm a grad student in a combustion engineering lab at the University of Connecticut (yes I know, please be kind) and am well aware of the dangers of explosives of any kind. The load I'm working with is safe, and I already have ~500 fired out of a K Frame. I'm merely curious from a theoretical standpoint.