This is just a weird thought as I'm trying to balance out weapon mods for a video game.
In handgun applications, of about 6" to 10" barrels, factory loaded, what would you consider to be more powerful? A .50 AE or a .45-70 Government?
As I'm attempting to find a good balance for my weapon mods I decided to do a little basic and probably completely irrelevant math. For sake of simplicity I just took examples of a number of cartridges and divided their muzzle energy by the length of the test barrel to come up with a basic ft-lb per barrel inch at the muzzle.
What I found was rather interesting... A .50 AE round has more energy per inch of barrel length than a .45-70 Government. I did quick digging and found some internet users speculating between the .500 S&W Magnum and the .45-70, stating that the .45-70 as a rifle cartridge uses slower burning powder to optimize it's performance from a longer barrel, while a cartridge like the .500 S&W uses quicker burning powder; and in a pistol application a .500 S&W would far surpass a .45-70.
Makes sense to me.
Here's what I come up with
.50AE with 1449 ft-lb of energy from a 6" test barrel has an average of 241.5 ft-lb per inch of barrel length at the muzzle. 300gr JHP
a .45-70G with 3449 ft-lb of energy from a 24" test barrel has an average of 143.7 ft-lb per inch of barrel length at the muzzle. 300gr JHP
From this, the .50AE would just barely edge out a .45-70 in a pistol application (10" or less barrel).
Input?
In handgun applications, of about 6" to 10" barrels, factory loaded, what would you consider to be more powerful? A .50 AE or a .45-70 Government?
As I'm attempting to find a good balance for my weapon mods I decided to do a little basic and probably completely irrelevant math. For sake of simplicity I just took examples of a number of cartridges and divided their muzzle energy by the length of the test barrel to come up with a basic ft-lb per barrel inch at the muzzle.
What I found was rather interesting... A .50 AE round has more energy per inch of barrel length than a .45-70 Government. I did quick digging and found some internet users speculating between the .500 S&W Magnum and the .45-70, stating that the .45-70 as a rifle cartridge uses slower burning powder to optimize it's performance from a longer barrel, while a cartridge like the .500 S&W uses quicker burning powder; and in a pistol application a .500 S&W would far surpass a .45-70.
Makes sense to me.
Here's what I come up with
.50AE with 1449 ft-lb of energy from a 6" test barrel has an average of 241.5 ft-lb per inch of barrel length at the muzzle. 300gr JHP
a .45-70G with 3449 ft-lb of energy from a 24" test barrel has an average of 143.7 ft-lb per inch of barrel length at the muzzle. 300gr JHP
From this, the .50AE would just barely edge out a .45-70 in a pistol application (10" or less barrel).
Input?