I've done alright in physics at school and remember all my formulas, including kinetic energy: E = (mv^2)/2
My question is not how to calculate kinetic energy but what is it in the barrel that yields more energy for a lighter bullet, ceteris paribus?
EG:
A) I load a 45acp with a 230-grain bullet and it does 850fps = 370 ft-lb of energy
B) I load the same shell with the SAME powder charge with a 185-grain and it does 1000fps = 411 ft-lb of energy
I understand that smaller bullet means that the same pressure will result in higher acceleration and therefore higher speed... And higher speed will result in exponentially higher energy - I get it!
But from an energy conservation point of view: The kinetic energy of the bullet comes from the chemical energy of the powder charge - surely there is no other source of energy...
So, how come the same powder charge is converted to different kinetic energies?
I know there's no magic, Energy=Energy.
Just wondering if anyone studied internal ballistics and can spare a few words on the mechanics of the barrel, to explain how lighter bullets convert energy more efficiently than heavier bullets?
(I'd actually think it should be the other way around: Heavier bullets spend more time inside the barrel and therefore have more time to pick up kinetic energy from the gas build up)
My question is not how to calculate kinetic energy but what is it in the barrel that yields more energy for a lighter bullet, ceteris paribus?
EG:
A) I load a 45acp with a 230-grain bullet and it does 850fps = 370 ft-lb of energy
B) I load the same shell with the SAME powder charge with a 185-grain and it does 1000fps = 411 ft-lb of energy
I understand that smaller bullet means that the same pressure will result in higher acceleration and therefore higher speed... And higher speed will result in exponentially higher energy - I get it!
But from an energy conservation point of view: The kinetic energy of the bullet comes from the chemical energy of the powder charge - surely there is no other source of energy...
So, how come the same powder charge is converted to different kinetic energies?
I know there's no magic, Energy=Energy.
Just wondering if anyone studied internal ballistics and can spare a few words on the mechanics of the barrel, to explain how lighter bullets convert energy more efficiently than heavier bullets?
(I'd actually think it should be the other way around: Heavier bullets spend more time inside the barrel and therefore have more time to pick up kinetic energy from the gas build up)