CAUTION: The following post includes a suggested loading approach not covered by currently published loads for this cartridge. USE AT YOUR OWN RISK. Neither the writer, The Firing Line, nor the staff of TFL assumes any liability for any damage or injury resulting from the use of this information.
I don't have a 7.5×55, but Hornady lists a 150-155-grain bullet getting a maximum of 46.1 grains of IMR4064, a 165-168-grain bullet getting a maximum of 43.2 grains of IMR4064 and a 180-grain bullet getting a maximum of 41.5 grains. As always, knock those down 10% and work up. QuickLOAD thinks, based on those data points, that 42.0-grains would be maximum with the 175-grain Sierra MatchKing. For Varget, the estimate would be 41.0 grains.
The reason I mentioned 4064 is Varget was originally designed to compete with it, so if 4064 works, so should Varget, in principle. They are not identical, though, so one approach is to get some 4064 and work up to those loads, then see if Varget can get you to the same velocities without pressure signs. I've done this in the .30-06 with good results.
For a calculated estimation, the graph below shows the starting and maximum loads for 4064 and Varget in the .30-06 with bullet weights from 110 grains to 220 grains taken from Hodgdon's data. The .30-06 is essentially a close caliber and case capacity pairing, and the Swiss at 55,000 psi maximum average pressure falls between the starting and maximum load pressure ranges for the .30-06, so I think the comparison is valid.
Basically, if you take 4064 maximum load data for the Swiss and multiply the powder charge weight by 0.98, that is going to be a very close estimate of the Varget maximum charge weight in this cartridge. You then knock 10% off the result and work up toward it in increments of 2% while watching for pressure signs. Note that this is not a universal formula. I have only checked that it is applicable to 30 cal cartridges close to 30-06 case capacity. Anything else would need to be checked, and, obviously, actual published data will be more reliable than this kind of estimate.