adjusting for distance

Using a 38 P+ 125 gr. HP in a 2" revolver what the deviation difference at 5 yards vs. 20 yards? Then using a 4" revolver same scenario? Then 50 yards, then 100 yards? All responses welcome.
 
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Best answer I can give you is to try it yourself.

My guess it that it may be about a foot low at twenty yards.

Bob Wright
 
Doc,

20 yards is not that far.

If you snub is sighted in at 7 yard, dead on, with the target right on the top of the front sight, I think it will be a few inches high at 20 at the most. 5 yards it might be 1/4 inch low.

The 4 incher would be just a bit differnt but not more than 1/2 inch.

Depends on what range you sighted your gun in more than anything.

Deaf
 
The easiest way to compare impact points at different distances is to look at trajectory charts

If you use a ballistics calculator, you can see how velocity affects the trajectories

It's largely dependent on the "zero" distance
 
What size target are you using?
Unless you're trying to put all the shots in the same hole,
My guess is not much difference until you get to around 50 yds.
I quite often practice at 50 yds with a .38 and a .45, and, with six inch circles, use about the same hold as for the 15 yd target.
Most shots hit near the center, (when they hit at all :))
 
P.S.
This conversation reminds me of what a retired ballistic physicist told me about how artillery is sighted in.
He said that all the computer and trajectory info is used about the way we use a bore sighter.
After that, it's shoot 'em and see where they land.
 
At seven yards just about any gun is going to hit about dead center. More than likely a .38 is sighted in with 158 gr. bullets. A 125 gr. pill is likely to print low as the range gets reasonable.

Bob Wright
 
Buffalo Bore shows their 125gr +P load, if sighted for zero at 25 yards, will be 1.22" low at fifty, and 10.2" low at a hundred.
The barrel length doesn't make much difference, but the longer barrel will have slightly higher muzzle velocity, so it won't drop quite as much.
 
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